-2x(x-3)+4=-)-x+1)

Solution for -2x(x-3)+4=-)-x+1) equation:

-2x(x-3)+4=-)-x+1)

We move all terms to the left:

-2x(x-3)+4-(-)-x+1))=0

We add all the numbers together, and all the variables

-2x(x-3)-x+4-0+1))=0

We add all the numbers together, and all the variables

-1x-2x(x-3)=0

We multiply parentheses

-2x^2-1x+6x=0

We add all the numbers together, and all the variables

-2x^2+5x=0

a = -2; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-2)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-2}=\frac{-10}{-4}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-2}=\frac{0}{-4}
=0
$