2x(x-3)+4x=-(-x+1)

Solution for 2x(x-3)+4x=-(-x+1) equation:

2x(x-3)+4x=-(-x+1)

We move all terms to the left:

2x(x-3)+4x-(-(-x+1))=0

We add all the numbers together, and all the variables

2x(x-3)+4x-(-(-1x+1))=0

We add all the numbers together, and all the variables

4x+2x(x-3)-(-(-1x+1))=0

We multiply parentheses

2x^2+4x-6x-(-(-1x+1))=0


We calculate terms in parentheses: -(-(-1x+1)), so:

-(-1x+1)

We get rid of parentheses

1x-1

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)


We add all the numbers together, and all the variables

2x^2-2x-(x-1)=0

We get rid of parentheses

2x^2-2x-x+1=0

We add all the numbers together, and all the variables

2x^2-3x+1=0

a = 2; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·2·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-1}{2*2}=\frac{2}{4}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+1}{2*2}=\frac{4}{4}
=1
$