2(3+2x)=20+(x-1)

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Solution for 2(3+2x)=20+(x-1) equation: 



2(3+2x)=20+(x-1)

We move all terms to the left:

2(3+2x)-(20+(x-1))=0

We add all the numbers together, and all the variables

2(2x+3)-(20+(x-1))=0

We multiply parentheses

4x-(20+(x-1))+6=0



We calculate terms in parentheses: -(20+(x-1)), so:

20+(x-1)

determiningTheFunctionDomain
(x-1)+20

We get rid of parentheses

x-1+20

We add all the numbers together, and all the variables

x+19

Back to the equation:

-(x+19)



We get rid of parentheses

4x-x-19+6=0

We add all the numbers together, and all the variables

3x-13=0

We move all terms containing x to the left, all other terms to the right

3x=13

x=13/3

x=4+1/3

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