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-2=2/5(3x+10)
We move all terms to the left:
-2-(2/5(3x+10))=0
Domain of the equation: 5(3x+10))!=0We multiply all the terms by the denominator
x∈R
-(2-2*5(3x+10))=0
We calculate terms in parentheses: -(2-2*5(3x+10)), so:We add all the numbers together, and all the variables
2-2*5(3x+10)
determiningTheFunctionDomain -2*5(3x+10)+2
Wy multiply elements
-10x(3+2
Back to the equation:
-(-10x(3+2)
-(-10x5=0
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