4(d-7)+3(5d-3)=1

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Solution for 4(d-7)+3(5d-3)=1 equation: 



4(d-7)+3(5d-3)=1

We move all terms to the left:

4(d-7)+3(5d-3)-(1)=0

We multiply parentheses

4d+15d-28-9-1=0

We add all the numbers together, and all the variables

19d-38=0

We move all terms containing d to the left, all other terms to the right

19d=38

d=38/19

d=2

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