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3(x+1)-(4x+2)=(6x+3)-4(3x-7)
We move all terms to the left:
3(x+1)-(4x+2)-((6x+3)-4(3x-7))=0
We multiply parentheses
3x-(4x+2)-((6x+3)-4(3x-7))+3=0
We get rid of parentheses
3x-4x-((6x+3)-4(3x-7))-2+3=0
We calculate terms in parentheses: -((6x+3)-4(3x-7)), so:We add all the numbers together, and all the variables
(6x+3)-4(3x-7)
We multiply parentheses
(6x+3)-12x+28
We get rid of parentheses
6x-12x+3+28
We add all the numbers together, and all the variables
-6x+31
Back to the equation:
-(-6x+31)
-1x-(-6x+31)+1=0
We get rid of parentheses
-1x+6x-31+1=0
We add all the numbers together, and all the variables
5x-30=0
We move all terms containing x to the left, all other terms to the right
5x=30
x=30/5
x=6
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