8-(4e-3)=e+3(5-2e)

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Solution for 8-(4e-3)=e+3(5-2e) equation: 



8-(4e-3)=e+3(5-2e)

We move all terms to the left:

8-(4e-3)-(e+3(5-2e))=0

We add all the numbers together, and all the variables

-(4e-3)-(e+3(-2e+5))+8=0

We get rid of parentheses

-4e-(e+3(-2e+5))+3+8=0



We calculate terms in parentheses: -(e+3(-2e+5)), so:

e+3(-2e+5)

We multiply parentheses

e-6e+15

We add all the numbers together, and all the variables

-5e+15

Back to the equation:

-(-5e+15)



We add all the numbers together, and all the variables

-4e-(-5e+15)+11=0

We get rid of parentheses

-4e+5e-15+11=0

We add all the numbers together, and all the variables

e-4=0

We move all terms containing e to the left, all other terms to the right

e=4

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