4(x-3)=2(1-x)+10x

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Solution for 4(x-3)=2(1-x)+10x equation: 



4(x-3)=2(1-x)+10x

We move all terms to the left:

4(x-3)-(2(1-x)+10x)=0

We add all the numbers together, and all the variables

4(x-3)-(2(-1x+1)+10x)=0

We multiply parentheses

4x-(2(-1x+1)+10x)-12=0



We calculate terms in parentheses: -(2(-1x+1)+10x), so:

2(-1x+1)+10x

We add all the numbers together, and all the variables

10x+2(-1x+1)

We multiply parentheses

10x-2x+2

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

4x-8x-2-12=0

We add all the numbers together, and all the variables

-4x-14=0

We move all terms containing x to the left, all other terms to the right

-4x=14

x=14/-4

x=-3+1/2

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