-2/3y+1/2(y-3)=y+1/4

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Solution for -2/3y+1/2(y-3)=y+1/4 equation: 



-2/3y+1/2(y-3)=y+1/4

We move all terms to the left:

-2/3y+1/2(y-3)-(y+1/4)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R





Domain of the equation: 2(y-3)!=0

y∈R



We add all the numbers together, and all the variables

-2/3y+1/2(y-3)-(+y+1/4)=0

We get rid of parentheses

-2/3y+1/2(y-3)-y-1/4=0

We calculate fractions


(-16yy/(24y^2y+48y/(24y^2y+(-12y^2)/(24y^2y-y=0

We can not solve this equation

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