36-6(7+y)=2(1+7y)

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Solution for 36-6(7+y)=2(1+7y) equation: 



36-6(7+y)=2(1+7y)

We move all terms to the left:

36-6(7+y)-(2(1+7y))=0

We add all the numbers together, and all the variables

-6(y+7)-(2(7y+1))+36=0

We multiply parentheses

-6y-(2(7y+1))-42+36=0



We calculate terms in parentheses: -(2(7y+1)), so:

2(7y+1)

We multiply parentheses

14y+2

Back to the equation:

-(14y+2)



We add all the numbers together, and all the variables

-6y-(14y+2)-6=0

We get rid of parentheses

-6y-14y-2-6=0

We add all the numbers together, and all the variables

-20y-8=0

We move all terms containing y to the left, all other terms to the right

-20y=8

y=8/-20

y=-2/5

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