24=-2(1b-3)+8

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Solution for 24=-2(1b-3)+8 equation: 



24=-2(1b-3)+8

We move all terms to the left:

24-(-2(1b-3)+8)=0

We add all the numbers together, and all the variables

-(-2(b-3)+8)+24=0



We calculate terms in parentheses: -(-2(b-3)+8), so:

-2(b-3)+8

We multiply parentheses

-2b+6+8

We add all the numbers together, and all the variables

-2b+14

Back to the equation:

-(-2b+14)



We get rid of parentheses

2b-14+24=0

We add all the numbers together, and all the variables

2b+10=0

We move all terms containing b to the left, all other terms to the right

2b=-10

b=-10/2

b=-5

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