-2(x2)-3(5-x)=2(3x-4x)+1

Solution for -2(x2)-3(5-x)=2(3x-4x)+1 equation:

-2(x2)-3(5-x)=2(3x-4x)+1

We move all terms to the left:

-2(x2)-3(5-x)-(2(3x-4x)+1)=0

We add all the numbers together, and all the variables

-2x2-3(-1x+5)-(2(-1x)+1)=0

We add all the numbers together, and all the variables

-2x^2-3(-1x+5)-(2(-1x)+1)=0

We multiply parentheses

-2x^2+3x-(2(-1x)+1)-15=0


We calculate terms in parentheses: -(2(-1x)+1), so:

2(-1x)+1

We multiply parentheses

-2x+1

Back to the equation:

-(-2x+1)


We get rid of parentheses

-2x^2+3x+2x-1-15=0

We add all the numbers together, and all the variables

-2x^2+5x-16=0

a = -2; b = 5; c = -16;
Δ = b2-4ac
Δ = 52-4·(-2)·(-16)
Δ = -103
Delta is less than zero, so there is no solution for the equation