-7(1-x-2)-(-3-x)=(2x-1)

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Solution for -7(1-x-2)-(-3-x)=(2x-1) equation: 



-7(1-x-2)-(-3-x)=(2x-1)

We move all terms to the left:

-7(1-x-2)-(-3-x)-((2x-1))=0

We add all the numbers together, and all the variables

-7(-1x-1)-(-1x-3)-((2x-1))=0

We multiply parentheses

7x-(-1x-3)-((2x-1))+7=0

We get rid of parentheses

7x+1x-((2x-1))+3+7=0



We calculate terms in parentheses: -((2x-1)), so:

(2x-1)

We get rid of parentheses

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

8x-(2x-1)+10=0

We get rid of parentheses

8x-2x+1+10=0

We add all the numbers together, and all the variables

6x+11=0

We move all terms containing x to the left, all other terms to the right

6x=-11

x=-11/6

x=-1+5/6

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