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s=3/2s-30
We move all terms to the left:
s-(3/2s-30)=0
Domain of the equation: 2s-30)!=0We get rid of parentheses
s∈R
s-3/2s+30=0
We multiply all the terms by the denominator
s*2s+30*2s-3=0
Wy multiply elements
2s^2+60s-3=0
a = 2; b = 60; c = -3;
Δ = b2-4ac
Δ = 602-4·2·(-3)
Δ = 3624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3624}=\sqrt{4*906}=\sqrt{4}*\sqrt{906}=2\sqrt{906}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{906}}{2*2}=\frac{-60-2\sqrt{906}}{4} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{906}}{2*2}=\frac{-60+2\sqrt{906}}{4} $
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