-2(3z+2)=2(-2z+2)

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Solution for -2(3z+2)=2(-2z+2) equation: 



-2(3z+2)=2(-2z+2)

We move all terms to the left:

-2(3z+2)-(2(-2z+2))=0

We multiply parentheses

-6z-(2(-2z+2))-4=0



We calculate terms in parentheses: -(2(-2z+2)), so:

2(-2z+2)

We multiply parentheses

-4z+4

Back to the equation:

-(-4z+4)



We get rid of parentheses

-6z+4z-4-4=0

We add all the numbers together, and all the variables

-2z-8=0

We move all terms containing z to the left, all other terms to the right

-2z=8

z=8/-2

z=-4

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