6y(-5y-10)=(y+11)(y+1)-y+31

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Solution for 6y(-5y-10)=(y+11)(y+1)-y+31 equation: 



6y(-5y-10)=(y+11)(y+1)-y+31

We move all terms to the left:

6y(-5y-10)-((y+11)(y+1)-y+31)=0

We multiply parentheses

-30y^2-60y-((y+11)(y+1)-y+31)=0

We multiply parentheses ..

-30y^2-((+y^2+y+11y+11)-y+31)-60y=0



We calculate terms in parentheses: -((+y^2+y+11y+11)-y+31), so:

(+y^2+y+11y+11)-y+31

We add all the numbers together, and all the variables

(+y^2+y+11y+11)-1y+31

We get rid of parentheses

y^2+y+11y-1y+11+31

We add all the numbers together, and all the variables

y^2+11y+42

Back to the equation:

-(y^2+11y+42)



We add all the numbers together, and all the variables

-30y^2-60y-(y^2+11y+42)=0

We get rid of parentheses

-30y^2-y^2-60y-11y-42=0

We add all the numbers together, and all the variables

-31y^2-71y-42=0

a = -31; b = -71; c = -42;
Δ = b2-4ac
Δ = -712-4·(-31)·(-42)
Δ = -167
Delta is less than zero, so there is no solution for the equation

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