2(y-6)+28=62-6(y+5)

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Solution for 2(y-6)+28=62-6(y+5) equation: 



2(y-6)+28=62-6(y+5)

We move all terms to the left:

2(y-6)+28-(62-6(y+5))=0

We multiply parentheses

2y-(62-6(y+5))-12+28=0



We calculate terms in parentheses: -(62-6(y+5)), so:

62-6(y+5)

determiningTheFunctionDomain
-6(y+5)+62

We multiply parentheses

-6y-30+62

We add all the numbers together, and all the variables

-6y+32

Back to the equation:

-(-6y+32)



We add all the numbers together, and all the variables

2y-(-6y+32)+16=0

We get rid of parentheses

2y+6y-32+16=0

We add all the numbers together, and all the variables

8y-16=0

We move all terms containing y to the left, all other terms to the right

8y=16

y=16/8

y=2

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