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-11(x+2)5(3x-6)=3(x-5)+10
We move all terms to the left:
-11(x+2)5(3x-6)-(3(x-5)+10)=0
We calculate terms in parentheses: -(3(x-5)+10), so:We get rid of parentheses
3(x-5)+10
We multiply parentheses
3x-15+10
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
-11(x+2)5(3x-6)-3x+5=0
We add all the numbers together, and all the variables
-3x-11(x+2)5(3x-6)+5=0
We move all terms containing x to the left, all other terms to the right
-3x-11(x+2)5(3x-6)=-5
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