2(v-1)=2v+6-2(3v-1)

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Solution for 2(v-1)=2v+6-2(3v-1) equation: 



2(v-1)=2v+6-2(3v-1)

We move all terms to the left:

2(v-1)-(2v+6-2(3v-1))=0

We multiply parentheses

2v-(2v+6-2(3v-1))-2=0



We calculate terms in parentheses: -(2v+6-2(3v-1)), so:

2v+6-2(3v-1)

determiningTheFunctionDomain
2v-2(3v-1)+6

We multiply parentheses

2v-6v+2+6

We add all the numbers together, and all the variables

-4v+8

Back to the equation:

-(-4v+8)



We get rid of parentheses

2v+4v-8-2=0

We add all the numbers together, and all the variables

6v-10=0

We move all terms containing v to the left, all other terms to the right

6v=10

v=10/6

v=1+2/3

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