-3(y+1)=6y-3+3(2y+3)

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Solution for -3(y+1)=6y-3+3(2y+3) equation: 



-3(y+1)=6y-3+3(2y+3)

We move all terms to the left:

-3(y+1)-(6y-3+3(2y+3))=0

We multiply parentheses

-3y-(6y-3+3(2y+3))-3=0



We calculate terms in parentheses: -(6y-3+3(2y+3)), so:

6y-3+3(2y+3)

determiningTheFunctionDomain
6y+3(2y+3)-3

We multiply parentheses

6y+6y+9-3

We add all the numbers together, and all the variables

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

-3y-12y-6-3=0

We add all the numbers together, and all the variables

-15y-9=0

We move all terms containing y to the left, all other terms to the right

-15y=9

y=9/-15

y=-3/5

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