7+2(2x-3)=-3(7x-3)+7x

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Solution for 7+2(2x-3)=-3(7x-3)+7x equation: 



7+2(2x-3)=-3(7x-3)+7x

We move all terms to the left:

7+2(2x-3)-(-3(7x-3)+7x)=0

We multiply parentheses

4x-(-3(7x-3)+7x)-6+7=0



We calculate terms in parentheses: -(-3(7x-3)+7x), so:

-3(7x-3)+7x

We add all the numbers together, and all the variables

7x-3(7x-3)

We multiply parentheses

7x-21x+9

We add all the numbers together, and all the variables

-14x+9

Back to the equation:

-(-14x+9)



We add all the numbers together, and all the variables

4x-(-14x+9)+1=0

We get rid of parentheses

4x+14x-9+1=0

We add all the numbers together, and all the variables

18x-8=0

We move all terms containing x to the left, all other terms to the right

18x=8

x=8/18

x=4/9

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