-10n2+35n=0

Solution for -10n2+35n=0 equation:

-10n^2+35n=0

a = -10; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-10)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-10}=\frac{-70}{-20}
=3+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-10}=\frac{0}{-20}
=0
$