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(5/2)+(5/2)y=2y-2
We move all terms to the left:
(5/2)+(5/2)y-(2y-2)=0
Domain of the equation: 2)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/2)y-(2y-2)+(+5/2)=0
We multiply parentheses
5y^2-(2y-2)+(+5/2)=0
We get rid of parentheses
5y^2-2y+2+5/2=0
We multiply all the terms by the denominator
5y^2*2-2y*2+5+2*2=0
We add all the numbers together, and all the variables
5y^2*2-2y*2+9=0
Wy multiply elements
10y^2-4y+9=0
a = 10; b = -4; c = +9;
Δ = b2-4ac
Δ = -42-4·10·9
Δ = -344
Delta is less than zero, so there is no solution for the equation
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