2x+3/2x+1+4x+7/2x+3=6(x+3)/2x+5

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Solution for 2x+3/2x+1+4x+7/2x+3=6(x+3)/2x+5 equation: 



2x+3/2x+1+4x+7/2x+3=6(x+3)/2x+5

We move all terms to the left:

2x+3/2x+1+4x+7/2x+3-(6(x+3)/2x+5)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 2x+5)!=0

x∈R



We add all the numbers together, and all the variables

6x+3/2x+7/2x-(6(x+3)/2x+5)+4=0

We calculate fractions


6x+14x/4x^2+(-(6(x+3)*2x)/4x^2+4=0

We calculate fractions

We do not support expression: x^4

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