2d+-6=2(d+2)-10

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Solution for 2d+-6=2(d+2)-10 equation:



2d+-6=2(d+2)-10
We move all terms to the left:
2d+-6-(2(d+2)-10)=0
We add all the numbers together, and all the variables
2d-(2(d+2)-10)=0
We calculate terms in parentheses: -(2(d+2)-10), so:
2(d+2)-10
We multiply parentheses
2d+4-10
We add all the numbers together, and all the variables
2d-6
Back to the equation:
-(2d-6)
We get rid of parentheses
2d-2d+6=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation

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