-(a-1)-(2a+1)=-4(a-2)+6

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Solution for -(a-1)-(2a+1)=-4(a-2)+6 equation: 



-(a-1)-(2a+1)=-4(a-2)+6

We move all terms to the left:

-(a-1)-(2a+1)-(-4(a-2)+6)=0

We get rid of parentheses

-a-2a-(-4(a-2)+6)+1-1=0



We calculate terms in parentheses: -(-4(a-2)+6), so:

-4(a-2)+6

We multiply parentheses

-4a+8+6

We add all the numbers together, and all the variables

-4a+14

Back to the equation:

-(-4a+14)



We add all the numbers together, and all the variables

-3a-(-4a+14)=0

We get rid of parentheses

-3a+4a-14=0

We add all the numbers together, and all the variables

a-14=0

We move all terms containing a to the left, all other terms to the right

a=14

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