2z/z+3=(3/z-10)+2

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Solution for 2z/z+3=(3/z-10)+2 equation: 



2z/z+3=(3/z-10)+2

We move all terms to the left:

2z/z+3-((3/z-10)+2)=0



Domain of the equation: z!=0

z∈R





Domain of the equation: z-10)+2)!=0

z∈R



We calculate fractions


2z^2/z^2+(-((3*z)/z^2+3=0

We add all the numbers together, and all the variables

2z^2/z^2+(-((+3z)/z^2+3=0

We calculate fractions

We do not support ezpression: z^4

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