4(x+3)-(2+3x)=-(2x-3+x)+5

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Solution for 4(x+3)-(2+3x)=-(2x-3+x)+5 equation: 



4(x+3)-(2+3x)=-(2x-3+x)+5

We move all terms to the left:

4(x+3)-(2+3x)-(-(2x-3+x)+5)=0

We add all the numbers together, and all the variables

4(x+3)-(3x+2)-(-(3x-3)+5)=0

We multiply parentheses

4x-(3x+2)-(-(3x-3)+5)+12=0

We get rid of parentheses

4x-3x-(-(3x-3)+5)-2+12=0



We calculate terms in parentheses: -(-(3x-3)+5), so:

-(3x-3)+5

We get rid of parentheses

-3x+3+5

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We add all the numbers together, and all the variables

x-(-3x+8)+10=0

We get rid of parentheses

x+3x-8+10=0

We add all the numbers together, and all the variables

4x+2=0

We move all terms containing x to the left, all other terms to the right

4x=-2

x=-2/4

x=-1/2

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