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3(x+5)=8+2(x-5)
We move all terms to the left:
3(x+5)-(8+2(x-5))=0
We multiply parentheses
3x-(8+2(x-5))+15=0
We calculate terms in parentheses: -(8+2(x-5)), so:We get rid of parentheses
8+2(x-5)
determiningTheFunctionDomain 2(x-5)+8
We multiply parentheses
2x-10+8
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
3x-2x+2+15=0
We add all the numbers together, and all the variables
x+17=0
We move all terms containing x to the left, all other terms to the right
x=-17
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