-(3x-7+3x)=3+6(2x-4)

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Solution for -(3x-7+3x)=3+6(2x-4) equation: 



-(3x-7+3x)=3+6(2x-4)

We move all terms to the left:

-(3x-7+3x)-(3+6(2x-4))=0

We add all the numbers together, and all the variables

-(6x-7)-(3+6(2x-4))=0

We get rid of parentheses

-6x-(3+6(2x-4))+7=0



We calculate terms in parentheses: -(3+6(2x-4)), so:

3+6(2x-4)

determiningTheFunctionDomain
6(2x-4)+3

We multiply parentheses

12x-24+3

We add all the numbers together, and all the variables

12x-21

Back to the equation:

-(12x-21)



We get rid of parentheses

-6x-12x+21+7=0

We add all the numbers together, and all the variables

-18x+28=0

We move all terms containing x to the left, all other terms to the right

-18x=-28

x=-28/-18

x=1+5/9

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