5+6(4c-3)=8c+16+9c+13

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Solution for 5+6(4c-3)=8c+16+9c+13 equation: 



5+6(4c-3)=8c+16+9c+13

We move all terms to the left:

5+6(4c-3)-(8c+16+9c+13)=0

We add all the numbers together, and all the variables

6(4c-3)-(17c+29)+5=0

We multiply parentheses

24c-(17c+29)-18+5=0

We get rid of parentheses

24c-17c-29-18+5=0

We add all the numbers together, and all the variables

7c-42=0

We move all terms containing c to the left, all other terms to the right

7c=42

c=42/7

c=6

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