-3(-7u+8)-6u=3(u-4)-3

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Solution for -3(-7u+8)-6u=3(u-4)-3 equation: 



-3(-7u+8)-6u=3(u-4)-3

We move all terms to the left:

-3(-7u+8)-6u-(3(u-4)-3)=0

We add all the numbers together, and all the variables

-6u-3(-7u+8)-(3(u-4)-3)=0

We multiply parentheses

-6u+21u-(3(u-4)-3)-24=0



We calculate terms in parentheses: -(3(u-4)-3), so:

3(u-4)-3

We multiply parentheses

3u-12-3

We add all the numbers together, and all the variables

3u-15

Back to the equation:

-(3u-15)



We add all the numbers together, and all the variables

15u-(3u-15)-24=0

We get rid of parentheses

15u-3u+15-24=0

We add all the numbers together, and all the variables

12u-9=0

We move all terms containing u to the left, all other terms to the right

12u=9

u=9/12

u=3/4

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