3(x+4)=11+2(3+x)

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Solution for 3(x+4)=11+2(3+x) equation: 



3(x+4)=11+2(3+x)

We move all terms to the left:

3(x+4)-(11+2(3+x))=0

We add all the numbers together, and all the variables

3(x+4)-(11+2(x+3))=0

We multiply parentheses

3x-(11+2(x+3))+12=0



We calculate terms in parentheses: -(11+2(x+3)), so:

11+2(x+3)

determiningTheFunctionDomain
2(x+3)+11

We multiply parentheses

2x+6+11

We add all the numbers together, and all the variables

2x+17

Back to the equation:

-(2x+17)



We get rid of parentheses

3x-2x-17+12=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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