(y-1)*(y-2)=(y-5)*(y-8)

Solution for (y-1)*(y-2)=(y-5)*(y-8) equation:

(y-1)(y-2)=(y-5)(y-8)

We move all terms to the left:

(y-1)(y-2)-((y-5)(y-8))=0

We multiply parentheses ..

(+y^2-2y-1y+2)-((y-5)(y-8))=0


We calculate terms in parentheses: -((y-5)(y-8)), so:

(y-5)(y-8)

We multiply parentheses ..

(+y^2-8y-5y+40)

We get rid of parentheses

y^2-8y-5y+40

We add all the numbers together, and all the variables

y^2-13y+40

Back to the equation:

-(y^2-13y+40)


We get rid of parentheses

y^2-y^2-2y-1y+13y+2-40=0

We add all the numbers together, and all the variables

10y-38=0

We move all terms containing y to the left, all other terms to the right

10y=38

y=38/10

y=3+4/5