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2x+14-34=4x-11x+4x(x-1)
We move all terms to the left:
2x+14-34-(4x-11x+4x(x-1))=0
We add all the numbers together, and all the variables
2x-(4x-11x+4x(x-1))-20=0
We calculate terms in parentheses: -(4x-11x+4x(x-1)), so:We get rid of parentheses
4x-11x+4x(x-1)
We add all the numbers together, and all the variables
-7x+4x(x-1)
We multiply parentheses
4x^2-7x-4x
We add all the numbers together, and all the variables
4x^2-11x
Back to the equation:
-(4x^2-11x)
-4x^2+2x+11x-20=0
We add all the numbers together, and all the variables
-4x^2+13x-20=0
a = -4; b = 13; c = -20;
Δ = b2-4ac
Δ = 132-4·(-4)·(-20)
Δ = -151
Delta is less than zero, so there is no solution for the equation
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