12x+32=19-6(5/3x-1

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Solution for 12x+32=19-6(5/3x-1 equation: 



12x+32=19-6(5/3x-1

We move all terms to the left:

12x+32-(19-6(5/3x-1)=0



Domain of the equation: 3x-1)+32!=0

x∈R



We multiply all the terms by the denominator


12x*3x-1)+32-(19-6(5=0

We add all the numbers together, and all the variables

12x*3x=0

Wy multiply elements

36x^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{72}=0$

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