2(x-2)/3=2(x+1)/6

Solution for 2(x-2)/3=2(x+1)/6 equation:

2(x-2)/3=2(x+1)/6

We move all terms to the left:

2(x-2)/3-(2(x+1)/6)=0

We calculate fractions


2x/()+(-(2(x+1)*3)/()=0


We calculate terms in parentheses: +(-(2(x+1)*3)/(), so:

-(2(x+1)*3)/(

We multiply all the terms by the denominator


-(2(x+1)*3)


We calculate terms in parentheses: -(2(x+1)*3), so:

2(x+1)*3

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)


We get rid of parentheses

-6x-6

Back to the equation:

+(-6x-6)


We get rid of parentheses

2x/()-6x-6=0

We multiply all the terms by the denominator


2x-6x*()-6*()=0

We add all the numbers together, and all the variables

2x-6x*()=0