(x-3)(2x+1-x)=x(x+2)

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Solution for (x-3)(2x+1-x)=x(x+2) equation: 



(x-3)(2x+1-x)=x(x+2)

We move all terms to the left:

(x-3)(2x+1-x)-(x(x+2))=0

We add all the numbers together, and all the variables

(x-3)(x+1)-(x(x+2))=0

We multiply parentheses ..

(+x^2+x-3x-3)-(x(x+2))=0



We calculate terms in parentheses: -(x(x+2)), so:

x(x+2)

We multiply parentheses

x^2+2x

Back to the equation:

-(x^2+2x)



We get rid of parentheses

x^2-x^2+x-3x-2x-3=0

We add all the numbers together, and all the variables

-4x-3=0

We move all terms containing x to the left, all other terms to the right

-4x=3

x=3/-4

x=-3/4

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