2+8x=17x2+8x=17x

Solution for 2+8x=17x2+8x=17x equation:

2+8x=17x^2+8x=17x

We move all terms to the left:

2+8x-(17x^2+8x)=0

We get rid of parentheses

-17x^2+8x-8x+2=0

We add all the numbers together, and all the variables

-17x^2+2=0

a = -17; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-17)·2
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{34}}{2*-17}=\frac{0-2\sqrt{34}}{-34}
=-\frac{2\sqrt{34}}{-34}
=-\frac{\sqrt{34}}{-17}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{34}}{2*-17}=\frac{0+2\sqrt{34}}{-34}
=\frac{2\sqrt{34}}{-34}
=\frac{\sqrt{34}}{-17}
$