(x-1)-(2x-2)=(2x-2)-(3x+5)

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Solution for (x-1)-(2x-2)=(2x-2)-(3x+5) equation: 



(x-1)-(2x-2)=(2x-2)-(3x+5)

We move all terms to the left:

(x-1)-(2x-2)-((2x-2)-(3x+5))=0

We get rid of parentheses

x-2x-((2x-2)-(3x+5))-1+2=0



We calculate terms in parentheses: -((2x-2)-(3x+5)), so:

(2x-2)-(3x+5)

We get rid of parentheses

2x-3x-2-5

We add all the numbers together, and all the variables

-1x-7

Back to the equation:

-(-1x-7)



We add all the numbers together, and all the variables

-1x-(-1x-7)+1=0

We get rid of parentheses

-1x+1x+7+1=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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