(x+4)/9=3-(x-4)/2

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Solution for (x+4)/9=3-(x-4)/2 equation: 



(x+4)/9=3-(x-4)/2

We move all terms to the left:

(x+4)/9-(3-(x-4)/2)=0

We calculate fractions


x/()+(-(3-(x-4)*9)/()=0



We calculate terms in parentheses: +(-(3-(x-4)*9)/(), so:

-(3-(x-4)*9)/(

We multiply all the terms by the denominator


-(3-(x-4)*9)



We calculate terms in parentheses: -(3-(x-4)*9), so:

3-(x-4)*9

determiningTheFunctionDomain
-(x-4)*9+3

We multiply parentheses

-9x+36+3

We add all the numbers together, and all the variables

-9x+39

Back to the equation:

-(-9x+39)



We get rid of parentheses

9x-39

Back to the equation:

+(9x-39)



We get rid of parentheses

x/()+9x-39=0

We multiply all the terms by the denominator


x+9x*()-39*()=0

We add all the numbers together, and all the variables

x+9x*()=0

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