6(x-3)=4x+10

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Solution for 6(x-3)=4x+10 equation: 



6(x-3)=4x+10

We move all terms to the left:

6(x-3)-(4x+10)=0

We multiply parentheses

6x-(4x+10)-18=0

We get rid of parentheses

6x-4x-10-18=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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