(x+10)+(x-1)+(x2)+(79)=360

Solution for (x+10)+(x-1)+(x2)+(79)=360 equation:

(x+10)+(x-1)+(x2)+(79)=360

We move all terms to the left:

(x+10)+(x-1)+(x2)+(79)-(360)=0

We add all the numbers together, and all the variables

x^2+(x+10)+(x-1)-281=0

We get rid of parentheses

x^2+x+x+10-1-281=0

We add all the numbers together, and all the variables

x^2+2x-272=0

a = 1; b = 2; c = -272;
Δ = b2-4ac
Δ = 22-4·1·(-272)
Δ = 1092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1092}=\sqrt{4*273}=\sqrt{4}*\sqrt{273}=2\sqrt{273}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{273}}{2*1}=\frac{-2-2\sqrt{273}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{273}}{2*1}=\frac{-2+2\sqrt{273}}{2}
$