4(6x-14)+8(6x+4)=12(10x+18)+6

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Solution for 4(6x-14)+8(6x+4)=12(10x+18)+6 equation: 



4(6x-14)+8(6x+4)=12(10x+18)+6

We move all terms to the left:

4(6x-14)+8(6x+4)-(12(10x+18)+6)=0

We multiply parentheses

24x+48x-(12(10x+18)+6)-56+32=0



We calculate terms in parentheses: -(12(10x+18)+6), so:

12(10x+18)+6

We multiply parentheses

120x+216+6

We add all the numbers together, and all the variables

120x+222

Back to the equation:

-(120x+222)



We add all the numbers together, and all the variables

72x-(120x+222)-24=0

We get rid of parentheses

72x-120x-222-24=0

We add all the numbers together, and all the variables

-48x-246=0

We move all terms containing x to the left, all other terms to the right

-48x=246

x=246/-48

x=-5+1/8

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