x+(2/3x)=30

Solution for x+(2/3x)=30 equation:

x+(2/3x)=30

We move all terms to the left:

x+(2/3x)-(30)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+2/3x)-30=0

We get rid of parentheses

x+2/3x-30=0

We multiply all the terms by the denominator


x*3x-30*3x+2=0

Wy multiply elements

3x^2-90x+2=0

a = 3; b = -90; c = +2;
Δ = b2-4ac
Δ = -902-4·3·2
Δ = 8076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8076}=\sqrt{4*2019}=\sqrt{4}*\sqrt{2019}=2\sqrt{2019}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{2019}}{2*3}=\frac{90-2\sqrt{2019}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{2019}}{2*3}=\frac{90+2\sqrt{2019}}{6}
$