I/3k+80=1/2k+120

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Solution for I/3k+80=1/2k+120 equation: 



/3I+80=1/2I+120

We move all terms to the left:

/3I+80-(1/2I+120)=0



Domain of the equation: 3I!=0

I!=0/3

I!=0

I∈R





Domain of the equation: 2I+120)!=0

I∈R



We get rid of parentheses

/3I-1/2I-120+80=0

We calculate fractions


(*2I)/6I^2+(-3I)/6I^2-120+80=0

We add all the numbers together, and all the variables

(+*2I)/6I^2+(-3I)/6I^2-120+80=0

We add all the numbers together, and all the variables

(+*2I)/6I^2+(-3I)/6I^2-40=0

We multiply all the terms by the denominator


(+*2I)+(-3I)-40*6I^2=0

Wy multiply elements

-240I^2+(+*2I)+(-3I)=0

We get rid of parentheses

-240I^2+*2I-3I=0

We add all the numbers together, and all the variables

-240I^2-3I+*2I=0

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