(b+5)+4b=29

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Solution for (b+5)+4b=29 equation: 



(b+5)+4b=29

We move all terms to the left:

(b+5)+4b-(29)=0

We add all the numbers together, and all the variables

4b+(b+5)-29=0

We get rid of parentheses

4b+b+5-29=0

We add all the numbers together, and all the variables

5b-24=0

We move all terms containing b to the left, all other terms to the right

5b=24

b=24/5

b=4+4/5

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