(a+3)(a+7)=a(a+3)-7

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Solution for (a+3)(a+7)=a(a+3)-7 equation: 



(a+3)(a+7)=a(a+3)-7

We move all terms to the left:

(a+3)(a+7)-(a(a+3)-7)=0

We multiply parentheses ..

(+a^2+7a+3a+21)-(a(a+3)-7)=0



We calculate terms in parentheses: -(a(a+3)-7), so:

a(a+3)-7

We multiply parentheses

a^2+3a-7

Back to the equation:

-(a^2+3a-7)



We get rid of parentheses

a^2-a^2+7a+3a-3a+21+7=0

We add all the numbers together, and all the variables

7a+28=0

We move all terms containing a to the left, all other terms to the right

7a=-28

a=-28/7

a=-4

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