-25=3(c-2)-3c

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Solution for -25=3(c-2)-3c equation: 



-25=3(c-2)-3c

We move all terms to the left:

-25-(3(c-2)-3c)=0



We calculate terms in parentheses: -(3(c-2)-3c), so:

3(c-2)-3c

We add all the numbers together, and all the variables

-3c+3(c-2)

We multiply parentheses

-3c+3c-6

We add all the numbers together, and all the variables

-6

Back to the equation:

-(-6)



We add all the numbers together, and all the variables

-19!=0

There is no solution for this equation

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