1/8(7t-9)=1/16(t+9)

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Solution for 1/8(7t-9)=1/16(t+9) equation: 



1/8(7t-9)=1/16(t+9)

We move all terms to the left:

1/8(7t-9)-(1/16(t+9))=0



Domain of the equation: 8(7t-9)!=0

t∈R





Domain of the equation: 16(t+9))!=0

t∈R



We calculate fractions


(16tt/(8(7t-9)*16(t+9)))+(-8t7/(8(7t-9)*16(t+9)))=0



We calculate terms in parentheses: +(16tt/(8(7t-9)*16(t+9))), so:

16tt/(8(7t-9)*16(t+9))

We multiply all the terms by the denominator


16tt

Back to the equation:

+(16tt)





We calculate terms in parentheses: +(-8t7/(8(7t-9)*16(t+9))), so:

-8t7/(8(7t-9)*16(t+9))

We multiply all the terms by the denominator


-8t7

We add all the numbers together, and all the variables

-8t^7

We do not support etpression: t^7

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